01-20-2018 18:15
01-20-2018 18:15
Hi everyone,
I have been looking to buy a Fitbit Blaze on Ebay for 80-100 dollars (USD). I am aware that it is not an authorized retailer. I really don't want to pay $200 from Fitbit or some of the other authorized retailers. I am scared that I may get scammed if I buy from Ebay. Is there any way Fitbit could give me a discount/promotion if I buy through them? I would like to buy through Fitbit because they could help me out with this problem. Any suggestions?
01-20-2018 20:46
01-20-2018 20:46
LOL No. You buy from ebay you are on your own. Best of luck to you!
Wendy | CA | Moto G6 Android
Want to discuss ways to increase your activity? Visit the Lifestyle Forum
01-21-2018 03:02
01-21-2018 03:02
Nope you missed your chance they had a long sale on Christmas to new year's.
Plus all the Fitbits I have ever had I bought them from auctions on eBay second hand aha 2 charge 2s one for me which I sold later for a blaze and one for my girlfriend.
Make sure you read the description and ask questions if needed and you are unsure.
If you buy the product and it doesn't match the description then you can get away with it contact eBay and they will sort everything out even if the seller says no returns accepted.
01-21-2018 10:05
01-21-2018 10:05
Unfortunately asking the community of Fitbit users will not get an answer to your question.
You could ask Fitbit support or keep an eye on the local sales. To be honest Fitbit users are not in the pissy ruin to grant your request.
01-04-2023 10:18 - edited 01-18-2023 00:12
01-04-2023 10:18 - edited 01-18-2023 00:12
Yes, you can buy a lot of useful goods on Ebay, but products like Fitbit must be bought in official stores. But when I read the Amazon or eBay customer service article, I started using Amazon more often. I am planning to make a big purchase and now I know where I will do it
01-04-2023 19:41
01-04-2023 19:41
Personally, I would not buy a 4-5 year old Fitbit. For one reason, if they didn't keep the battery properly charged, the battery will not be good.