Passive calorie burnout metrics

[SunsetRunner]

I realized that even if you aren’t wearing your device, it continues to capture calorie burn out. When contacted chat support, they mentioned it’s passive calorie burn out basis your BMR parameters. However, I don’t see a clear math to calculate this burn out. Can anyone explain how this is calculated?

[JohnnyRow]

Your BMR (basal metabolic rate) calorie burn is based on age, gender, height, and weight.  There are a few different scientific formulas for calculating this, based on the above.  I have seen which formula Fitbit uses but forget which one it is.  However they all come out very close on the daily calorie burn.  You can do web search on BMR calculators and find a few different ones and compare results, but make sure you are just inputting above parameters to get BMR, and not activity levels which will give you other numbers.

[SunsetRunner]

Thank you Johnny, however the calculation using BMR is based on fixed parameters and those aren’t changed that frequently. What I see is the static approach to calculate the same for a living body which isn’t accurate enough. You can say in “ideal” condition but that’s not how it’s projected. It has to be presented separately and not mixed with active calorie burn out metrics which happens through exercise, etc. 

[JohnnyRow]

So is what you are asking just how to find what number is Fitbit using for BMR for you? I'm afraid if I told you how to get that, you would just complain about how Fitbit is presenting it.  But just look at minimum hourly calorie burn overnight, and multiply that times 24.  Or you saw what it was capturing when you were not wearing it.

[SunsetRunner]

If the device is presenting a data and we as users are supposed to believe it, then it has to be accurate than calculated using hypothetical assumptions. Whatever way the device/software is calculating should have some logical math because we trust it. But it’s made basis come calculations then they break my trust. Have to complain/provide feedback.